program to generate and print armstrong numbers

program to generate and print armstrong numbers
armstrong number in c: This program prints armstrong number. In our program we ask the user to enter a number and then we use a loop from one to the entered number and check if it is an armstrong number and if it is then the number is printed on the screen. Remember a number is armstrong if the sum of cubes of individual digits of a number is equal to the number itself. For example 371 is an armstrong number as 33 + 73 + 13 = 371. Some other armstrong numbers are 0, 1, 153, 370, 407.

C code
#include 

#include 

 main() {

 int r;

 long number = 0, c, sum = 0, temp;

 printf("Enter the maximum range upto which you want to find armstrong numbers ");

 scanf("%ld",&number);

 printf("Following armstrong numbers are found from 1 to %ld\n",number);

 for( c = 1 ; c <= number ; c++ ) { 

 temp = c;

 while( temp != 0 ) {

 r = temp%10;

 sum = sum + r*r*r;

 temp = temp/10; 

 }

 if ( c == sum )

 printf("%ld\n", c);

 sum = 0;

 }

 getch();

 return 0; 

}

Output of program

armstrong number

armstrong number c program

  c programming code to check whether a number is armstrong or not. A number is armstrong if the sum of cubes of individual digits of a number is equal to the number itself. For example 371 is an armstrong number as 33 + 73 + 13 = 371. Some other armstrong numbers are: 0, 1, 153, 370, 407.

C programming code
#include  

 main() {

 int number, sum = 0, temp, remainder;

 printf("Enter a number\n");

 scanf("%d",&number);

 temp = number;

 while( temp != 0 ) { 

 remainder = temp%10;

 sum = sum + remainder*remainder*remainder; 

 temp = temp/10;

 }

 if ( number == sum )

 printf("Entered number is an armstrong number."); 

    else 

     printf("Entered number is not an armstrong number."); 

 return 0; 

}

Output of program:

Prime number program

Prime number program in c language

#include 

   main() {

  int n, i = 3, count, c;

  printf("Enter the number of prime numbers required\n");

 scanf("%d",&n);  

if ( n >= 1 ) {

  printf("First %d prime numbers are :\n",n);

 printf("2\n");

 }

 for ( count = 2 ; count <= n ; ) {

 for ( c = 2 ; c <= i - 1 ; c++ ) {

 if ( i%c == 0 )

 break;

 }

 if ( c == i ) { 

 printf("%d\n",i);

 count++; 

 }

 i++;

 }

 return 0; 

}

There are many logic to check prime numbers, one given below is more efficient then above method.
for ( c = 2 ; c <= (int)sqrt(n) ; c++ )
//only checking from 2 to square root of number is sufficient.


C program for prime number or not
#include

 main() { 

 int n, c = 2; 

 printf("Enter a number to check if it is prime\n"); 

 scanf("%d",&n);

 for ( c = 2 ; c <= n - 1 ; c++ ) {

 if ( n%c == 0 ) {

 printf("%d is not prime.\n", n);

 break;

 }

 }

 if ( c == n ) 

 printf("%d is prime.\n", n); 

 return 0; 

}

C program for prime number using function
#include

 int check_prime(int);

 main() {

 int n, result;

 printf("Enter an integer to check whether it is prime or not.\n");

 scanf("%d",&n); 

 result = check_prime(n);

 if ( result == 1 )

 printf("%d is prime.\n", n);

 else

 printf("%d is not prime.\n", n);

 return 0;

 }

 int check_prime(int a) {

 int c;

 for ( c = 2 ; c <= a - 1 ; c++ ) {

 if ( a%c == 0 )

 return 0;

 }

 if ( c == a )

 return 1;

 }

to print diamond pattern

c program to print diamond pattern

Diamond pattern in c: This code print diamond pattern of stars. Diamond shape is as follows:

     * 

   *** 

 ***** 

   ***

     * 

#include  

 int main() {

 int n, c, k, space = 1;

 printf("Enter number of rows\n");

 scanf("%d", &n);

 space = n - 1; 

 for (k = 1; k <= n; k++) { 

   for (c = 1; c <= space; c++) 

      printf(" "); 

       space--; 

 for (c = 1; c <= 2*k-1; c++)

   printf("*");

    printf("\n"); 

     }

 space = 1; 

      for (k = 1; k <= n - 1; k++) { 

       for (c = 1; c <= space; c++)

         printf(" ");

           space++;

               for (c = 1 ; c <= 2*(n-k)-1; c++)

                printf("*");

                 printf("\n");

                } 

                 return 0;

  }

To print Pattern

#include 

 main() {

 int row, c, n, temp;

 printf("Enter the number of rows in pyramid of stars you wish to see ");

 scanf("%d",&n); 

 temp = n;

 for ( row = 1 ; row <= n ; row++ ) {

 for ( c = 1 ; c < temp ; c++ ) 

     printf(" ");

           temp--;

 for ( c = 1 ; c <= 2*row - 1 ; c++ )

 printf("*");

 printf("\n"); 

 } 

 return 0;

 }

Output:



Consider the pattern
*
**
***
****
*****

to print above pattern see the code below:

#include

 main() { 

 int n, c, k;

 printf("Enter number of rows\n");

 scanf("%d",&n); 

 for ( c = 1 ; c <= n ; c++ ) { 

 for( k = 1 ; k <= c ; k++ ) 

 printf("*");

 printf("\n");

 }

 return 0;

 }

Palindrome number

#include

 main() {

 int n, reverse = 0, temp; 

 printf("Enter a number to check if it is a palindrome or not\n");

 scanf("%d",&n);

 temp = n; 

 while( temp != 0 ) {

 reverse = reverse * 10;

 reverse = reverse + temp%10; 

 temp = temp/10;

 }

 if ( n == reverse ) 

 printf("%d is a palindrome number.\n", n); 

    else

       printf("%d is not a palindrome number.\n", n); 

 return 0;

 }

Reverse a Number

#include

 main() {

 int n, reverse = 0;

 printf("Enter a number to reverse\n");

 scanf("%d",&n);

 while (n != 0) {

 reverse = reverse * 10;

 reverse = reverse + n%10;

 n = n/10;

 }

 printf("Reverse of entered number is = %d\n", reverse);

 return 0;

 }

Output of program:

Swapping of two number

Swapping of two numbers in c

#include

 int main() {

 int x, y, temp;

 printf("Enter the value of x and y\n");

 scanf("%d%d", &x, &y);

 printf("Before Swapping\nx = %d\ny = %d\n",x,y);

 temp = x; x = y; y = temp;

 printf("After Swapping\nx = %d\ny = %d\n",x,y);

 return 0;

 }

Swapping of two numbers without third variable: You can also swap two numbers without using temp or temporary or third variable. In that case c program will be as shown :-

#include  

 int main() { 

 int a, b; 

 printf("Enter two integers to swap\n");

 scanf("%d%d", &a, &b);

 a = a + b; 

 b = a - b;

 a = a - b;

 printf("a = %d\nb = %d\n",a,b); 

 return 0; 

}

Swap two numbers using pointers

#include  

 int main() { 

 int x, y, *a, *b, temp;

 printf("Enter the value of x and y\n"); 

 scanf("%d%d", &x, &y); 

 printf("Before Swapping\nx = %d\ny = %d\n", x, y);

 a = &x; 

 b = &y;

 temp = *b; 

 *b = *a;

 *a = temp; 

 printf("After Swapping\nx = %d\ny = %d\n", x, y);

 return 0;

 }

Swapping numbers using call by reference

#include  

 void swap(int*, int*);

 int main() { 

 int x, y;

 printf("Enter the value of x and y\n"); 

 scanf("%d%d",&x,&y);

 printf("Before Swapping\nx = %d\ny = %d\n", x, y);

 swap(&x, &y); 

 printf("After Swapping\nx = %d\ny = %d\n", x, y);

 return 0; 

} 

 void swap(int *a, int *b) { 

 int temp; 

 temp = *b; 

 *b = *a;

 *a = temp; 

 }

C programming code to swap using bitwise XOR

#include  

 int main() { 

 int x, y;

 scanf("%d%d", &x, &y);

 printf("x = %d\ny = %d\n", x, y);

 x = x ^ y; 

 y = x ^ y;

 x = x ^ y;

 printf("x = %d\ny = %d\n", x, y);

 return 0; 

}

Output of code:

to Add n Numbers

#include  

 int main() { 

 int n, sum = 0, c, value;

 printf("Enter the number of integers you want to add\n");

 scanf("%d", &n); 

 printf("Enter %d integers\n",n);

     for (c = 1; c <= n; c++)

     { 

       scanf("%d",&value); 

         sum = sum + value; 

      }

 printf("Sum of entered integers = %d\n",sum); 

 return 0;

 }

Output of program:

C programming code using array

#include  

 int main() { 

 int n, sum = 0, c, array[100];

 scanf("%d", &n); 

 for (c = 0; c < n; c++) {

 scanf("%d", &array[c]);

 sum = sum + array[c];

 }

 printf("Sum = %d\n",sum); 

 return 0;

 }

add digits of number

#include

 main() {

 int n, sum = 0, remainder;

 printf("Enter an integer\n");

 scanf("%d",&n); 

 while(n != 0) {

 remainder = n % 10;

 sum = sum + remainder;

 n = n / 10;

 }

 printf("Sum of digits of entered number = %d\n",sum); 

 return 0; 

}

Add digits using recursion
#include  

 int add_digits(int);

 int main() { 

 int n, result;

 scanf("%d", &n); 

 result = add_digits(n);

 printf("%d\n", result);

 return 0; 

}

 int add_digits(int n) { 

 static int sum = 0;

 if (n == 0) 

{

 return 0;

 } 

 sum = n%10 + add_digits(n/10);

 return sum;

 }

Factorial

Factorial program in c using for loop


#include
#include
main()
{
int c, n, fact = 1;
printf("Enter a number to calculate it's factorial\n");
scanf("%d",&n);

for( c = 1 ; c <= n ; c++ )
fact = fact*c;

printf("Factorial of %d = %d\n",n,fact);
getch();
return 0;
}

Factorial program in c using function

#include
long factorial(int);
main()
{
int number;
long fact = 1;

printf("Enter a number to calculate it's factorial\n");
scanf("%d",&number);
printf("%d! = %ld\n", number, factorial(number));
return 0;
}

long factorial(int n)
{
int c;
long result = 1;
for( c = 1 ; c <= n ; c++ )

result = result*c;

return ( result );

}

Factorial program in c using recursion

#include

long factorial(int);
main()
{
int num;
long f;
printf("ENTER A NUMBER TO FIND FACTORIAL :");
scanf("%d",&num);

if(num<0)
printf("NEGATIVE NUMBERS ARE NOT ALLOWED");
else
{
f = factorial(num);
printf("%d!=%ld",num,f);
}
return(0);
}

long factorial(int n)

{
if(n==0)
return(1);
else
return(n*factorial(n-1));
}

Vowel or Not

#include

main()
{
char ch;
printf("Enter a character\n");
scanf("%c", &ch);

if (ch == 'a' || ch == 'A'  || ch == 'e'  || ch == 'E'  || ch == 'i' || ch == 'I' || ch =='o' || ch=='O'  || ch == 'u'  ||  ch == 'U')

printf("%c is a vowel.\n", ch);

else

printf("%c is not a vowel.\n", ch);
return 0;
}

Check vowel using switch:

#include
main()
{
char ch;
printf("Enter a character\n");
scanf("%c", &ch);

switch(ch)
{
case 'a':
case 'A':
case 'e':
case 'E':
case 'i':
case 'I':
case 'o':
case 'O':
case 'u':
case 'U':

printf("%c is a vowel.\n", ch);
break;

default: printf("%c is not a vowel.\n", ch);

}
return 0;
}

Function to check vowel

int check_vowel(char a)
{
 if (a >= 'A' && a <= 'Z')
a = a + 'a' - 'A'; /* Converting to lower case or use a = a + 32 */

if (a == 'a' || a == 'e' || a == 'i' || a == 'o' || a == 'u')

return 1;
return 0;
}

program to check whether input alphabet is a vowel or not

check out odd or even

C program to check odd or even using modulus operator:

#include

main()
{
int n;
printf("Enter an integer\n");
scanf("%d",&n);

if ( n%2 == 0 )

printf("Even\n");
else
printf("Odd\n");

return 0;
}

C program to check odd or even using bitwise operator

#include

main()

{

int n;

printf("Enter an integer\n");

scanf("%d",&n);

 if ( n & 1 == 1 )

 printf("Odd\n");
else
 printf("Even\n");
return 0;
}


C program to check odd or even without using bitwise or modulus operator


#include

main()

{

int n;



printf("Enter an integer\n");

scanf("%d",&n);

if ( (n/2)*2 == n )

 printf("Even\n");

else

printf("Odd\n");

 return 0;

}


Find odd or even using conditional operator


#include

main()

{

int n;


printf("Enter an integer\n");

scanf("%d",&n);



n%2 == 0 ? printf("Even number\n") : printf("Odd number\n");
return 0;
}